An entire branch of chemical thermodynamics requires no more than the first law. The important feature of thermochemistry is that qP tells about energy inherent in chemical interactions.
For a reaction
the enthalpy of reaction is written
At P=1 bar, we have the Standard enthalpy of reaction
| H(2) > H(1) | exothermic (exo="out of") | DrHo > 0 |
| H(2) < H(1) | exothermic (endo="into") | DrHo < 0 |
Consider the reaction
The enthalpy of reaction is expressed per mole. Per mole
of what?
We may write a general reaction as
where nJ are the stoichiometric coefficients
Note nJ < 0 for reactants, nJ >0 for products. (For the above reaction, nA=-1,
nB = -2, nC = +2,
and nD = +3).
We may define the extent of reaction x such that the number
of moles of J consumed or formed by the reaction.
x has units of moles. DrHo refers specifically
to =1 mole.
Thus, DrHo is per mole of reaction as written. For the reactions.
DrHo(2) = ½DrHo(1)
| Symbol | Process | Transition |
| DfusHo | fusion | solid ® liquid |
| DvapHo | vaporization | liquid ® vapor |
| DsubHo | sublimation | solid ® vapor |
| DtrsHo | phase transition | phasea ® phase b |
| DmixHo | mixing | pure A, B ® A,B solution |
| DsolHo | solution | A + solvent ® solution of A |
| DhydHo | hydration | A ® A(aq) |
| DionHo | ionization | A(g) ® A+(g) + e-(g) |
| DfHo | formation | ref. elements ® compound |
| DcHo | combustion | compound + O2(g) ® CO2(g) + H2O (l) (+N2(g) ?) |
| DatHo | atomization | compound(g) ® elements (atomic g) |
| Ho(A-B) | bond dissociation | A-B(g) ® A(g) + B(g) |
| DecHo | electron gain | A(g) + e-(g) ® A-(g) |
Notes:
Consider the indefinite integral
How do we find the constant of integration C?
Define a zero for the function H: Choose H=Ho=0 for a standard state, then integrate from that state.
The standard state of liquid and solid substances is the
pure substance at P=1 bar.
The standard state of a gaseous substance is the pure
ideal gas at P=1 bar.
The standard state may be defined for any T. (typically tabulated for 298K).
The reference state of a substance at a given T is its most stable form at standard pressure and the given T. Important reference state elements include graphite carbon and diatomic gases, e.g., C(graphite), H2(g), O2(g), N2(g).
A formation reaction is reference state elements ® compound.
Example: formation of liquid benzene, C6H6
(l)
6C(gr) + 3H2(g)® C6H6(l)
DrHo for this process is Ho(C6H6(l)) - 6Ho (C(gr)) - 3Ho(H2(g)). If we define the H of the reference state elements to be 0, then DrHo for the formation reaction is DfHo of the product.
There are two practical consequences of the state function properties of H.
This picture shows that we can write
That is, we can use enthalpies of formation instead of absolute enthalpies in the calculation of a reaction enthalpy.
Fixed volume apparatus: measures DUo (qV)
In order to measure the heat transferred from the temperature change of the calorimeter, the CV (CP) of the calorimeter must be known. This is assumed to be much larger than the CV of the reactants and products.
2 approaches (K stands for calorimeter):
(1) measure CV,K by burning a standard sample with known DU, measuring DT
(2) measure CV,K by heating the bath with a known current
for a known time (VIt=energy) and measuring DT
We want DU for reactants and products at the same T. We really measure the DT caused by the reaction in an insulated, constant V vessel. The difference between U of the experimental final state and the desired final state can be found from CV of the calorimeter.
Essentially a thermostat that scans the temperature of the sample in slow, controlled way. Measures power dissipated in sample per unit time. (dq/dt). Since the temperature scan rate is known (dT/dt), the heat capacity dqP/dT is measured.
Dr Ho = Dr Uo+Dr (PoVo) = Dr Uo+PoDr Vo
Note that DrVo is calculated just
like any other energy quantity of reaction:
Simplifications:
For most reactions near STP, it is reasonable to neglect the molar volumes of condensed-phase substances relative to those of gaseous substances.
Since the gaseous standard state is ideal behavior,
for each gas, and
Thus,
DrHo = DrUo
+ DngasRT
Example
aA(s) + bB(g) ® cC(g)
+ dD(g) + eE(l)
Neglecting volumes of A and E: DrVo
= cVom,C + dVom,D
- bVom,B = (c+d-b)RT/Po
(Dngas = c+d-b )